Sherlock Holmes, Sir Arthur Conan Doyle, Christian Rode, Peter Groeger, Stephan Schwartz's 'Teil 7 - Die Originale - Fall 42: Das Rätsel von Boscrome Valley' came out on August 14, 2015. The duration of Teil 7 - Die Originale - Fall 42: Das Rätsel von Boscrome Valley is about 3 minutes long, at 3:01. Based on our data, "Teil 7 - Die Originale - Fall 42: Das Rätsel von Boscrome Valley" appears to be safe for all ages and is not considered explicit. This track is about the average length of a typical track. The song is number 7 out of 17 in Die Originale - Fall 42: Das Rätsel von Boscrome Valley by Sherlock Holmes. Going off of the ISRC code of this track, we detected that the origin of this track is from Germany. Based on our statistics, Teil 7 - Die Originale - Fall 42: Das Rätsel von Boscrome Valley's popularity is below average in popularity right now. Although the overall vibe is very danceable, it does project more negative sounds.

Teil 7 - Die Originale - Fall 42: Das Rätsel von Boscrome Valley テンポ

The tempo marking of Teil 7 - Die Originale - Fall 42: Das Rätsel von Boscrome Valley by Sherlock Holmes, Sir Arthur Conan Doyle, Christian Rode, Peter Groeger, Stephan Schwartz is Allegro (fast, quick, and bright), since this song has a tempo of 122 テンポ. With that information, we can conclude that the song has a fast tempo. This song can go great with walking. The time signature for this track is 5/4.

Teil 7 - Die Originale - Fall 42: Das Rätsel von Boscrome Valley キー

This song has a musical key of B Minor. This also means that this song has a camelot key of 10A. So, the perfect camelot match for 10A would be either 10A or 9B. While, a low energy boost can consist of either 10B or 11A. For moderate energy boost, you would use 7A and a high energy boost can either be 12A or 5A. However, if you are looking for a low energy drop, finding a song with a camelot key of 9A would be a great choice. Where 1A would give you a moderate drop, and 8A or 3A would be a high energy drop. Lastly, 1B allows you to change the mood.