Kapitel 133 - Mister Park Lane - Mister-Reihe, Teil 4 - Louise Bay, Jenny Laura Bischoff, Alexander Schwarz Information

Louise Bay, Jenny Laura Bischoff, Alexander Schwarz made "Kapitel 133 - Mister Park Lane - Mister-Reihe, Teil 4" available on October 28, 2022. The duration of Kapitel 133 - Mister Park Lane - Mister-Reihe, Teil 4 is about 3 minutes long, at 3:09. Based on our data, "Kapitel 133 - Mister Park Lane - Mister-Reihe, Teil 4" appears to be safe for all ages and is not considered explicit. This track is about the average length of a typical track. The track order of this song in Louise Bay's "Mister Park Lane [Mister-Reihe, Teil 4 (Ungekürzt)]" album is number 46 out of 175. On top of that, Germany appears to be the country where this track was created. In terms of popularity, Kapitel 133 - Mister Park Lane - Mister-Reihe, Teil 4 is currently not that popular. The overall tone is very danceable, especially with its high energy, which produces more of a euphoric, cheerful, or happy vibe.

Kapitel 133 - Mister Park Lane - Mister-Reihe, Teil 4 BPM

We consider the tempo marking of Kapitel 133 - Mister Park Lane - Mister-Reihe, Teil 4 by Louise Bay, Jenny Laura Bischoff, Alexander Schwarz to be Andante (at a walking pace) because the track has a tempo of 107 BPM, a half-time of 54BPM, and a double-time of 214 BPM. Based on that, the speed of the song's tempo is slow. The time signature for this track is 3/4.

Kapitel 133 - Mister Park Lane - Mister-Reihe, Teil 4 Key

This song is in the music key of D♭ Major. This also means that this song has a camelot key of 3B. So, the perfect camelot match for 3B would be either 3B or 4A. While, 4B can give you a low energy boost. For moderate energy boost, you would use 12B and a high energy boost can either be 5B or 10B. Though, if you want a low energy drop, you should looking for songs with either a camelot key of 3A or 2B will give you a low energy drop, 6B would be a moderate one, and 1B or 8B would be a high energy drop. Lastly, 12A allows you to change the mood.