Teil 11 - Die Originale - Fall 40: Der goldene Kneifer
Sherlock Holmes, Sir Arthur Conan Doyle, Christian Rode, Peter Groeger, Stephan Schwartz
Die Originale - Fall 40: Der goldene Kneifer
3:02 July 31, 2015
BPM
46
Key
E♭ Minor
Camelot
2A

Embed

Share Link

Teil 11 - Die Originale - Fall 40: Der goldene Kneifer - Sherlock Holmes, Sir Arthur Conan Doyle, Christian Rode, Peter Groeger, Stephan Schwartz Information

Acousticness
82%
Danceability
76%
Energy
33%
Instrumentalness
0%
Liveness
55%
Loudness
72%
Speechiness
95%
Valence
55%
Popularity
Loudness
-17.01 dB

Summary

Sherlock Holmes, Sir Arthur Conan Doyle, Christian Rode, Peter Groeger, Stephan Schwartz made "Teil 11 - Die Originale - Fall 40: Der goldene Kneifer" available on July 31, 2015. The duration of Teil 11 - Die Originale - Fall 40: Der goldene Kneifer is about 3 minutes long, at 3:02. Based on our data, "Teil 11 - Die Originale - Fall 40: Der goldene Kneifer" appears to be safe for all ages and is not considered explicit. This track is about the average length of a typical track. The song is number 11 out of 23 in Die Originale - Fall 40: Der goldene Kneifer by Sherlock Holmes. Going off of the ISRC code of this track, we detected that the origin of this track is from Germany. Teil 11 - Die Originale - Fall 40: Der goldene Kneifer is below average in popularity right now. Even with the track produces more of a neutral energy, it is pretty danceable compared to others.

Teil 11 - Die Originale - Fall 40: Der goldene Kneifer BPM

The tempo marking of Teil 11 - Die Originale - Fall 40: Der goldene Kneifer by Sherlock Holmes, Sir Arthur Conan Doyle, Christian Rode, Peter Groeger, Stephan Schwartz is Lento (slowly), since this song has a tempo of 46 BPM. With that information, we can conclude that the song has a slow tempo. The time signature for this track is 4/4.

Teil 11 - Die Originale - Fall 40: Der goldene Kneifer Key

This song has a musical key of E♭ Minor. Because this track belongs in the E♭ Minor key, the camelot key is 2A. So, the perfect camelot match for 2A would be either 2A or 1B. While, a low energy boost can consist of either 2B or 3A. For moderate energy boost, you would use 11A and a high energy boost can either be 4A or 9A. However, if you are looking for a low energy drop, finding a song with a camelot key of 1A would be a great choice. Where 5A would give you a moderate drop, and 12A or 7A would be a high energy drop. Lastly, 5B allows you to change the mood.

Recommendations

TrackArtistKeyEnergyCamelotBPM
07 - Das Totenhaus der Lady Florence - Teil 05 by Larry Brent07 - Das Totenhaus der Lady Florence - Teil 05Larry BrentB Minor610A109 BPM
Teil 10 - Die Originale - Fall 37: Die einsame Radfahrerin by Sherlock Holmes, Sir Arthur Conan Doyle, Christian Rode, Peter Groeger, Stephan SchwartzTeil 10 - Die Originale - Fall 37: Die einsame RadfahrerinSherlock Holmes, Sir Arthur Conan Doyle, Christian Rode, Peter Groeger, Stephan SchwartzB♭ Minor73A128 BPM
Warrior Princess Kapitel 13 by Mord ist ihr LebenWarrior Princess Kapitel 13Mord ist ihr LebenD♭ Minor612A61 BPM
02 - Spuren im Moor (Zweiter Fall) - Teil 09 by Sherlock Holmes02 - Spuren im Moor (Zweiter Fall) - Teil 09Sherlock HolmesB Major31B149 BPM
01 - Der Hund von Baskerville - Teil 15 by Sherlock Holmes01 - Der Hund von Baskerville - Teil 15Sherlock HolmesF♯ Major72B86 BPM
14 - Abenteuer in der Geisterbibliothek - Teil 22 by HUI BUH neue Welt14 - Abenteuer in der Geisterbibliothek - Teil 22HUI BUH neue WeltF Major67B82 BPM
03 - Mutanten - Teil 20 by Perry Rhodan03 - Mutanten - Teil 20Perry RhodanC Major28B113 BPM
133 - und der Esel in der Tropfsteinhöhle - Teil 31 by Fünf Freunde133 - und der Esel in der Tropfsteinhöhle - Teil 31Fünf FreundeA♭ Major64B98 BPM
Kapitel 7 - Der aufregende Mondflug by Weltraum-AbenteuerKapitel 7 - Der aufregende MondflugWeltraum-AbenteuerD♭ Major63B86 BPM
17 - Der Meisterdetektiv - Teil 20 by HUI BUH neue Welt17 - Der Meisterdetektiv - Teil 20HUI BUH neue WeltB Major61B122 BPM
ISRC
DEUD92180386
Label
L-M Records/RCA Records

Section: 0.4345278739929199

End: 0.4377713203430176