On December 31, 1899, the song "Wild Eyed Woman" was released by Bob Luman. The duration of Wild Eyed Woman is about two minutes long, specifically at 2:09. This song does not appear to have any foul language. Wild Eyed Woman's duration is considered a little bit shorter than the average duration of a typical track. There are a total of 18 in the song's album "The Essential Bob Luman, Vol 1". In this album, this song's track order is #14. In terms of popularity, Wild Eyed Woman is currently unknown. The overall tone is very danceable, especially with its high energy, which produces more of a euphoric, cheerful, or happy vibe.
With Wild Eyed Woman by Bob Luman having a BPM of 112 with a half-time of 56 BPM and a double-time of 224 BPM, we would consider this track to have a Moderato (at a moderate speed) tempo marking. Because of this, we believe that the song has an overall moderate tempo. The time signature for this track is 4/4.
A Major is the music key of this track. Or for those who are familiar with the camelot wheel, this song has a camelot key of 11B. So, the perfect camelot match for 11B would be either 11B or 12A. While, 12B can give you a low energy boost. For moderate energy boost, you would use 8B and a high energy boost can either be 1B or 6B. Though, if you want a low energy drop, you should looking for songs with either a camelot key of 11A or 10B will give you a low energy drop, 2B would be a moderate one, and 9B or 4B would be a high energy drop. Lastly, 8A allows you to change the mood.
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